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464=8x^2
We move all terms to the left:
464-(8x^2)=0
a = -8; b = 0; c = +464;
Δ = b2-4ac
Δ = 02-4·(-8)·464
Δ = 14848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14848}=\sqrt{256*58}=\sqrt{256}*\sqrt{58}=16\sqrt{58}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{58}}{2*-8}=\frac{0-16\sqrt{58}}{-16} =-\frac{16\sqrt{58}}{-16} =-\frac{\sqrt{58}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{58}}{2*-8}=\frac{0+16\sqrt{58}}{-16} =\frac{16\sqrt{58}}{-16} =\frac{\sqrt{58}}{-1} $
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